16y^2-40xy+25x^2=

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Solution for 16y^2-40xy+25x^2= equation:


Simplifying
16y2 + -40xy + 25x2 = 0

Reorder the terms:
-40xy + 25x2 + 16y2 = 0

Solving
-40xy + 25x2 + 16y2 = 0

Solving for variable 'x'.

Factor a trinomial.
(5x + -4y)(5x + -4y) = 0

Subproblem 1

Set the factor '(5x + -4y)' equal to zero and attempt to solve: Simplifying 5x + -4y = 0 Solving 5x + -4y = 0 Move all terms containing x to the left, all other terms to the right. Add '4y' to each side of the equation. 5x + -4y + 4y = 0 + 4y Combine like terms: -4y + 4y = 0 5x + 0 = 0 + 4y 5x = 0 + 4y Remove the zero: 5x = 4y Divide each side by '5'. x = 0.8y Simplifying x = 0.8y

Subproblem 2

Set the factor '(5x + -4y)' equal to zero and attempt to solve: Simplifying 5x + -4y = 0 Solving 5x + -4y = 0 Move all terms containing x to the left, all other terms to the right. Add '4y' to each side of the equation. 5x + -4y + 4y = 0 + 4y Combine like terms: -4y + 4y = 0 5x + 0 = 0 + 4y 5x = 0 + 4y Remove the zero: 5x = 4y Divide each side by '5'. x = 0.8y Simplifying x = 0.8y

Solution

x = {0.8y, 0.8y}

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